-sin(x)+2cos(2x)=0

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Solution for -sin(x)+2cos(2x)=0 equation:


Simplifying
-1sin(x) + 2cos(2x) = 0

Multiply ins * x
-1insx + 2cos(2x) = 0

Remove parenthesis around (2x)
-1insx + 2cos * 2x = 0

Reorder the terms for easier multiplication:
-1insx + 2 * 2cos * x = 0

Multiply 2 * 2
-1insx + 4cos * x = 0

Multiply cos * x
-1insx + 4cosx = 0

Reorder the terms:
4cosx + -1insx = 0

Solving
4cosx + -1insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add 'insx' to each side of the equation.
4cosx + -1insx + insx = 0 + insx

Combine like terms: -1insx + insx = 0
4cosx + 0 = 0 + insx
4cosx = 0 + insx
Remove the zero:
4cosx = insx

Divide each side by '4osx'.
c = 0.25ino-1

Simplifying
c = 0.25ino-1

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