-sin(x)+cos(2x)=0

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Solution for -sin(x)+cos(2x)=0 equation:


Simplifying
-1sin(x) + cos(2x) = 0

Multiply ins * x
-1insx + cos(2x) = 0

Remove parenthesis around (2x)
-1insx + cos * 2x = 0

Reorder the terms for easier multiplication:
-1insx + 2cos * x = 0

Multiply cos * x
-1insx + 2cosx = 0

Reorder the terms:
2cosx + -1insx = 0

Solving
2cosx + -1insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add 'insx' to each side of the equation.
2cosx + -1insx + insx = 0 + insx

Combine like terms: -1insx + insx = 0
2cosx + 0 = 0 + insx
2cosx = 0 + insx
Remove the zero:
2cosx = insx

Divide each side by '2osx'.
c = 0.5ino-1

Simplifying
c = 0.5ino-1

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