-t+65+4t+3=2(7t-65)

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Solution for -t+65+4t+3=2(7t-65) equation:



-t+65+4t+3=2(7t-65)
We move all terms to the left:
-t+65+4t+3-(2(7t-65))=0
We add all the numbers together, and all the variables
3t-(2(7t-65))+68=0
We calculate terms in parentheses: -(2(7t-65)), so:
2(7t-65)
We multiply parentheses
14t-130
Back to the equation:
-(14t-130)
We get rid of parentheses
3t-14t+130+68=0
We add all the numbers together, and all the variables
-11t+198=0
We move all terms containing t to the left, all other terms to the right
-11t=-198
t=-198/-11
t=+18

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