-t+65+4t+3=2(7t-65)

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Solution for -t+65+4t+3=2(7t-65) equation: 



-t+65+4t+3=2(7t-65)

We move all terms to the left:

-t+65+4t+3-(2(7t-65))=0

We add all the numbers together, and all the variables

3t-(2(7t-65))+68=0



We calculate terms in parentheses: -(2(7t-65)), so:

2(7t-65)

We multiply parentheses

14t-130

Back to the equation:

-(14t-130)



We get rid of parentheses

3t-14t+130+68=0

We add all the numbers together, and all the variables

-11t+198=0

We move all terms containing t to the left, all other terms to the right

-11t=-198

t=-198/-11

t=+18

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