-t-1/3=1/2*(t-1)

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Solution for -t-1/3=1/2*(t-1) equation: 



-t-1/3=1/2(t-1)

We move all terms to the left:

-t-1/3-(1/2(t-1))=0



Domain of the equation: 2(t-1))!=0

t∈R



We add all the numbers together, and all the variables

-1t-(1/2(t-1))-1/3=0

We calculate fractions


-1t+()/6t+(-2tt/6t=0

We multiply all the terms by the denominator


-1t*6t+(-2tt+()=0



We calculate terms in parentheses: +(-2tt+(), so:

-2tt+(

We add all the numbers together, and all the variables

-2tt

Back to the equation:

+(-2tt)



Wy multiply elements

-6t^2+(-2tt)=0

We get rid of parentheses

-6t^2-2tt=0

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