-v-5(3v-3)=7+5(7-5v)

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Solution for -v-5(3v-3)=7+5(7-5v) equation:



-v-5(3v-3)=7+5(7-5v)
We move all terms to the left:
-v-5(3v-3)-(7+5(7-5v))=0
We add all the numbers together, and all the variables
-v-5(3v-3)-(7+5(-5v+7))=0
We add all the numbers together, and all the variables
-1v-5(3v-3)-(7+5(-5v+7))=0
We multiply parentheses
-1v-15v-(7+5(-5v+7))+15=0
We calculate terms in parentheses: -(7+5(-5v+7)), so:
7+5(-5v+7)
determiningTheFunctionDomain 5(-5v+7)+7
We multiply parentheses
-25v+35+7
We add all the numbers together, and all the variables
-25v+42
Back to the equation:
-(-25v+42)
We add all the numbers together, and all the variables
-16v-(-25v+42)+15=0
We get rid of parentheses
-16v+25v-42+15=0
We add all the numbers together, and all the variables
9v-27=0
We move all terms containing v to the left, all other terms to the right
9v=27
v=27/9
v=3

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