-w+1/4(w-12)=3

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Solution for -w+1/4(w-12)=3 equation: 



-w+1/4(w-12)=3

We move all terms to the left:

-w+1/4(w-12)-(3)=0



Domain of the equation: 4(w-12)!=0

w∈R



We add all the numbers together, and all the variables

-1w+1/4(w-12)-3=0

We multiply all the terms by the denominator


-1w*4(w-12)-3*4(w-12)+1=0

Wy multiply elements

-4w^2(w-12w(w+1=0

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