-x(-3)+2(x+2)=-(x-2)+3x-(x-2)

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Solution for -x(-3)+2(x+2)=-(x-2)+3x-(x-2) equation: 



-x(-3)+2(x+2)=-(x-2)+3x-(x-2)

We move all terms to the left:

-x(-3)+2(x+2)-(-(x-2)+3x-(x-2))=0

We multiply parentheses

3x+2x-(-(x-2)+3x-(x-2))+4=0



We calculate terms in parentheses: -(-(x-2)+3x-(x-2)), so:

-(x-2)+3x-(x-2)

We add all the numbers together, and all the variables

3x-(x-2)-(x-2)

We get rid of parentheses

3x-x-x+2+2

We add all the numbers together, and all the variables

x+4

Back to the equation:

-(x+4)



We add all the numbers together, and all the variables

5x-(x+4)+4=0

We get rid of parentheses

5x-x-4+4=0

We add all the numbers together, and all the variables

4x=0

x=0/4

x=0

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