-x(x+4)+5=4x+5x

Solution for -x(x+4)+5=4x+5x equation:

-x(x+4)+5=4x+5x

We move all terms to the left:

-x(x+4)+5-(4x+5x)=0

We add all the numbers together, and all the variables

-x(x+4)-(+9x)+5=0

We multiply parentheses

-x^2-4x-(+9x)+5=0

We get rid of parentheses

-x^2-4x-9x+5=0

We add all the numbers together, and all the variables

-1x^2-13x+5=0

a = -1; b = -13; c = +5;
Δ = b2-4ac
Δ = -132-4·(-1)·5
Δ = 189
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{189}=\sqrt{9*21}=\sqrt{9}*\sqrt{21}=3\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-3\sqrt{21}}{2*-1}=\frac{13-3\sqrt{21}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+3\sqrt{21}}{2*-1}=\frac{13+3\sqrt{21}}{-2}
$