-x(x+4)+5=4x-15x

Solution for -x(x+4)+5=4x-15x equation:

-x(x+4)+5=4x-15x

We move all terms to the left:

-x(x+4)+5-(4x-15x)=0

We add all the numbers together, and all the variables

-x(x+4)-(-11x)+5=0

We multiply parentheses

-x^2-4x-(-11x)+5=0

We get rid of parentheses

-x^2-4x+11x+5=0

We add all the numbers together, and all the variables

-1x^2+7x+5=0

a = -1; b = 7; c = +5;
Δ = b2-4ac
Δ = 72-4·(-1)·5
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{69}}{2*-1}=\frac{-7-\sqrt{69}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{69}}{2*-1}=\frac{-7+\sqrt{69}}{-2}
$