-x(x-2)=3(2x+3)

Solution for -x(x-2)=3(2x+3) equation:

-x(x-2)=3(2x+3)

We move all terms to the left:

-x(x-2)-(3(2x+3))=0

We multiply parentheses

-x^2+2x-(3(2x+3))=0


We calculate terms in parentheses: -(3(2x+3)), so:

3(2x+3)

We multiply parentheses

6x+9

Back to the equation:

-(6x+9)


We add all the numbers together, and all the variables

-1x^2+2x-(6x+9)=0

We get rid of parentheses

-1x^2+2x-6x-9=0

We add all the numbers together, and all the variables

-1x^2-4x-9=0

a = -1; b = -4; c = -9;
Δ = b2-4ac
Δ = -42-4·(-1)·(-9)
Δ = -20
Delta is less than zero, so there is no solution for the equation