-x+1/2=y/3;-x/3=y-5

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Solution for -x+1/2=y/3;-x/3=y-5 system of equations: 


  • /| 1/2-x-(y/3) = 0| 5-x/3-y = 0
  • We try to solve the equation: 1/2-x-(y/3) = 0
  • 1/2-x-1/3*y = 0 // - 1/2-x
  • -1/3*y = -(1/2-x) // : -1/3
  • y = (-(1/2-x))/(-1/3)
  • y = -3*(x-1/2)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 5-(-3*(x-1/2))-x/3 = 0| y = -3*(x-1/2)
  • 5-3*(-1)*(x-1/2)-x/3 = 0
  • 8/3*x-3/2+5 = 0
  • 8/3*x+7/2 = 0
  • 8/3*x+7/2 = 0 // - 7/2
  • 8/3*x = -7/2 // : 8/3
  • x = -7/2/8/3
  • x = -21/16
  • We insert the solution into one of the initial equations of our system of equations
  • For y = -3*(x-1/2): 
  • y = -3*(-21/16-1/2)
  • y = -3*(-(1/2+21/16))
  • y = -3*(-29/16)
  • y = 29/16*3
  • y = 87/16
  • We get a system of equations:
  • /| y = 87/16| x = -21/16

 

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