-x+10+5x=3-(x-12)

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Solution for -x+10+5x=3-(x-12) equation: 



-x+10+5x=3-(x-12)

We move all terms to the left:

-x+10+5x-(3-(x-12))=0

We add all the numbers together, and all the variables

4x-(3-(x-12))+10=0



We calculate terms in parentheses: -(3-(x-12)), so:

3-(x-12)

determiningTheFunctionDomain
-(x-12)+3

We get rid of parentheses

-x+12+3

We add all the numbers together, and all the variables

-1x+15

Back to the equation:

-(-1x+15)



We get rid of parentheses

4x+1x-15+10=0

We add all the numbers together, and all the variables

5x-5=0

We move all terms containing x to the left, all other terms to the right

5x=5

x=5/5

x=1

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