-x+2(-x-2)=3+4(-x+1)

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Solution for -x+2(-x-2)=3+4(-x+1) equation: 



-x+2(-x-2)=3+4(-x+1)

We move all terms to the left:

-x+2(-x-2)-(3+4(-x+1))=0

We add all the numbers together, and all the variables

-x+2(-1x-2)-(3+4(-1x+1))=0

We add all the numbers together, and all the variables

-1x+2(-1x-2)-(3+4(-1x+1))=0

We multiply parentheses

-1x-2x-(3+4(-1x+1))-4=0



We calculate terms in parentheses: -(3+4(-1x+1)), so:

3+4(-1x+1)

determiningTheFunctionDomain
4(-1x+1)+3

We multiply parentheses

-4x+4+3

We add all the numbers together, and all the variables

-4x+7

Back to the equation:

-(-4x+7)



We add all the numbers together, and all the variables

-3x-(-4x+7)-4=0

We get rid of parentheses

-3x+4x-7-4=0

We add all the numbers together, and all the variables

x-11=0

We move all terms containing x to the left, all other terms to the right

x=11

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