-x+2(x+3)=2-5(x-8)

Solution for -x+2(x+3)=2-5(x-8) equation:

-x+2(x+3)=2-5(x-8)

We move all terms to the left:

-x+2(x+3)-(2-5(x-8))=0

We add all the numbers together, and all the variables

-1x+2(x+3)-(2-5(x-8))=0

We multiply parentheses

-1x+2x-(2-5(x-8))+6=0


We calculate terms in parentheses: -(2-5(x-8)), so:

2-5(x-8)

determiningTheFunctionDomain
-5(x-8)+2

We multiply parentheses

-5x+40+2

We add all the numbers together, and all the variables

-5x+42

Back to the equation:

-(-5x+42)


We add all the numbers together, and all the variables

x-(-5x+42)+6=0

We get rid of parentheses

x+5x-42+6=0

We add all the numbers together, and all the variables

6x-36=0

We move all terms containing x to the left, all other terms to the right

6x=36

x=36/6

x=6