-x+29=3(2x-4)+6

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Solution for -x+29=3(2x-4)+6 equation: 



-x+29=3(2x-4)+6

We move all terms to the left:

-x+29-(3(2x-4)+6)=0

We add all the numbers together, and all the variables

-1x-(3(2x-4)+6)+29=0



We calculate terms in parentheses: -(3(2x-4)+6), so:

3(2x-4)+6

We multiply parentheses

6x-12+6

We add all the numbers together, and all the variables

6x-6

Back to the equation:

-(6x-6)



We get rid of parentheses

-1x-6x+6+29=0

We add all the numbers together, and all the variables

-7x+35=0

We move all terms containing x to the left, all other terms to the right

-7x=-35

x=-35/-7

x=+5

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