-x+2=(3/5)x-6

Solution for -x+2=(3/5)x-6 equation:

-x+2=(3/5)x-6

We move all terms to the left:

-x+2-((3/5)x-6)=0


Domain of the equation: 5)x-6)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-x-((+3/5)x-6)+2=0

We add all the numbers together, and all the variables

-1x-((+3/5)x-6)+2=0

We multiply all the terms by the denominator


-1x*5)x-6)-((+2*5)x-6)+3=0

We add all the numbers together, and all the variables

-1x*5)x-6)-(10x-6)+3=0

Wy multiply elements

-5x^2=0

a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-10}=0$