-x+3(x-2)=2(x-2)-3

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Solution for -x+3(x-2)=2(x-2)-3 equation:


Simplifying
-1x + 3(x + -2) = 2(x + -2) + -3

Reorder the terms:
-1x + 3(-2 + x) = 2(x + -2) + -3
-1x + (-2 * 3 + x * 3) = 2(x + -2) + -3
-1x + (-6 + 3x) = 2(x + -2) + -3

Reorder the terms:
-6 + -1x + 3x = 2(x + -2) + -3

Combine like terms: -1x + 3x = 2x
-6 + 2x = 2(x + -2) + -3

Reorder the terms:
-6 + 2x = 2(-2 + x) + -3
-6 + 2x = (-2 * 2 + x * 2) + -3
-6 + 2x = (-4 + 2x) + -3

Reorder the terms:
-6 + 2x = -4 + -3 + 2x

Combine like terms: -4 + -3 = -7
-6 + 2x = -7 + 2x

Add '-2x' to each side of the equation.
-6 + 2x + -2x = -7 + 2x + -2x

Combine like terms: 2x + -2x = 0
-6 + 0 = -7 + 2x + -2x
-6 = -7 + 2x + -2x

Combine like terms: 2x + -2x = 0
-6 = -7 + 0
-6 = -7

Solving
-6 = -7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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