-x+32=4(4x-3)+10

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Solution for -x+32=4(4x-3)+10 equation:



-x+32=4(4x-3)+10
We move all terms to the left:
-x+32-(4(4x-3)+10)=0
We add all the numbers together, and all the variables
-1x-(4(4x-3)+10)+32=0
We calculate terms in parentheses: -(4(4x-3)+10), so:
4(4x-3)+10
We multiply parentheses
16x-12+10
We add all the numbers together, and all the variables
16x-2
Back to the equation:
-(16x-2)
We get rid of parentheses
-1x-16x+2+32=0
We add all the numbers together, and all the variables
-17x+34=0
We move all terms containing x to the left, all other terms to the right
-17x=-34
x=-34/-17
x=+2

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