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-x+3=21/2x-4
We move all terms to the left:
-x+3-(21/2x-4)=0
Domain of the equation: 2x-4)!=0We add all the numbers together, and all the variables
x∈R
-1x-(21/2x-4)+3=0
We get rid of parentheses
-1x-21/2x+4+3=0
We multiply all the terms by the denominator
-1x*2x+4*2x+3*2x-21=0
Wy multiply elements
-2x^2+8x+6x-21=0
We add all the numbers together, and all the variables
-2x^2+14x-21=0
a = -2; b = 14; c = -21;
Δ = b2-4ac
Δ = 142-4·(-2)·(-21)
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{7}}{2*-2}=\frac{-14-2\sqrt{7}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{7}}{2*-2}=\frac{-14+2\sqrt{7}}{-4} $
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