-x+4=2(x-4)/5

Solution for -x+4=2(x-4)/5 equation:

-x+4=2(x-4)/5

We move all terms to the left:

-x+4-(2(x-4)/5)=0

We add all the numbers together, and all the variables

-1x-(2(x-4)/5)+4=0

We multiply all the terms by the denominator


-1x*5)-(2(x-4)+4*5)=0

We add all the numbers together, and all the variables

-1x*5)-(2(x-4)=0

Wy multiply elements

-5x^2=0

a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-10}=0$