-x+5=3(2x-4)+10

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Solution for -x+5=3(2x-4)+10 equation:



-x+5=3(2x-4)+10
We move all terms to the left:
-x+5-(3(2x-4)+10)=0
We add all the numbers together, and all the variables
-1x-(3(2x-4)+10)+5=0
We calculate terms in parentheses: -(3(2x-4)+10), so:
3(2x-4)+10
We multiply parentheses
6x-12+10
We add all the numbers together, and all the variables
6x-2
Back to the equation:
-(6x-2)
We get rid of parentheses
-1x-6x+2+5=0
We add all the numbers together, and all the variables
-7x+7=0
We move all terms containing x to the left, all other terms to the right
-7x=-7
x=-7/-7
x=1

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