-x-19=2(2x+3)+10

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Solution for -x-19=2(2x+3)+10 equation: 



-x-19=2(2x+3)+10

We move all terms to the left:

-x-19-(2(2x+3)+10)=0

We add all the numbers together, and all the variables

-1x-(2(2x+3)+10)-19=0



We calculate terms in parentheses: -(2(2x+3)+10), so:

2(2x+3)+10

We multiply parentheses

4x+6+10

We add all the numbers together, and all the variables

4x+16

Back to the equation:

-(4x+16)



We get rid of parentheses

-1x-4x-16-19=0

We add all the numbers together, and all the variables

-5x-35=0

We move all terms containing x to the left, all other terms to the right

-5x=35

x=35/-5

x=-7

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