-x-2(-x-3)-(-x+2)=-2(x+1)

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Solution for -x-2(-x-3)-(-x+2)=-2(x+1) equation: 



-x-2(-x-3)-(-x+2)=-2(x+1)

We move all terms to the left:

-x-2(-x-3)-(-x+2)-(-2(x+1))=0

We add all the numbers together, and all the variables

-x-2(-1x-3)-(-1x+2)-(-2(x+1))=0

We add all the numbers together, and all the variables

-1x-2(-1x-3)-(-1x+2)-(-2(x+1))=0

We multiply parentheses

-1x+2x-(-1x+2)-(-2(x+1))+6=0

We get rid of parentheses

-1x+2x+1x-(-2(x+1))-2+6=0



We calculate terms in parentheses: -(-2(x+1)), so:

-2(x+1)

We multiply parentheses

-2x-2

Back to the equation:

-(-2x-2)



We add all the numbers together, and all the variables

2x-(-2x-2)+4=0

We get rid of parentheses

2x+2x+2+4=0

We add all the numbers together, and all the variables

4x+6=0

We move all terms containing x to the left, all other terms to the right

4x=-6

x=-6/4

x=-1+1/2

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