-x-2(-x-3)-(-x+2)=-2(x+1)

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Solution for -x-2(-x-3)-(-x+2)=-2(x+1) equation:



-x-2(-x-3)-(-x+2)=-2(x+1)
We move all terms to the left:
-x-2(-x-3)-(-x+2)-(-2(x+1))=0
We add all the numbers together, and all the variables
-x-2(-1x-3)-(-1x+2)-(-2(x+1))=0
We add all the numbers together, and all the variables
-1x-2(-1x-3)-(-1x+2)-(-2(x+1))=0
We multiply parentheses
-1x+2x-(-1x+2)-(-2(x+1))+6=0
We get rid of parentheses
-1x+2x+1x-(-2(x+1))-2+6=0
We calculate terms in parentheses: -(-2(x+1)), so:
-2(x+1)
We multiply parentheses
-2x-2
Back to the equation:
-(-2x-2)
We add all the numbers together, and all the variables
2x-(-2x-2)+4=0
We get rid of parentheses
2x+2x+2+4=0
We add all the numbers together, and all the variables
4x+6=0
We move all terms containing x to the left, all other terms to the right
4x=-6
x=-6/4
x=-1+1/2

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