-x-2(2x+1)=3(-x)+-10

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Solution for -x-2(2x+1)=3(-x)+-10 equation: 



-x-2(2x+1)=3(-x)+-10

We move all terms to the left:

-x-2(2x+1)-(3(-x)+-10)=0

We add all the numbers together, and all the variables

-x-2(2x+1)-(3(-1x)+-10)=0

We add all the numbers together, and all the variables

-1x-2(2x+1)-(3(-1x)+-10)=0

We use the square of the difference formula

-1x-2(2x+1)-(3(-1x)-10)=0

We multiply parentheses

-1x-4x-(3(-1x)-10)-2=0



We calculate terms in parentheses: -(3(-1x)-10), so:

3(-1x)-10

We multiply parentheses

-3x-10

Back to the equation:

-(-3x-10)



We add all the numbers together, and all the variables

-5x-(-3x-10)-2=0

We get rid of parentheses

-5x+3x+10-2=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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