-x-2(2x+1)=3-x+(-10)

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Solution for -x-2(2x+1)=3-x+(-10) equation: 



-x-2(2x+1)=3-x+(-10)

We move all terms to the left:

-x-2(2x+1)-(3-x+(-10))=0

We add all the numbers together, and all the variables

-1x-2(2x+1)-(3-x+(-10))=0

We multiply parentheses

-1x-4x-(3-x+(-10))-2=0



We calculate terms in parentheses: -(3-x+(-10)), so:

3-x+(-10)

determiningTheFunctionDomain
-x+3+(-10)

We add all the numbers together, and all the variables

-1x-7

Back to the equation:

-(-1x-7)



We add all the numbers together, and all the variables

-5x-(-1x-7)-2=0

We get rid of parentheses

-5x+1x+7-2=0

We add all the numbers together, and all the variables

-4x+5=0

We move all terms containing x to the left, all other terms to the right

-4x=-5

x=-5/-4

x=1+1/4

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