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-x-2=-1/2x-2
We move all terms to the left:
-x-2-(-1/2x-2)=0
Domain of the equation: 2x-2)!=0We add all the numbers together, and all the variables
x∈R
-1x-(-1/2x-2)-2=0
We get rid of parentheses
-1x+1/2x+2-2=0
We multiply all the terms by the denominator
-1x*2x+2*2x-2*2x+1=0
Wy multiply elements
-2x^2+4x-4x+1=0
We add all the numbers together, and all the variables
-2x^2+1=0
a = -2; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-2)·1
Δ = 8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8}=\sqrt{4*2}=\sqrt{4}*\sqrt{2}=2\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{2}}{2*-2}=\frac{0-2\sqrt{2}}{-4} =-\frac{2\sqrt{2}}{-4} =-\frac{\sqrt{2}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{2}}{2*-2}=\frac{0+2\sqrt{2}}{-4} =\frac{2\sqrt{2}}{-4} =\frac{\sqrt{2}}{-2} $
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