-x-2x-(3-2x)=2(x-1)

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Solution for -x-2x-(3-2x)=2(x-1) equation: 



-x-2x-(3-2x)=2(x-1)

We move all terms to the left:

-x-2x-(3-2x)-(2(x-1))=0

We add all the numbers together, and all the variables

-x-2x-(-2x+3)-(2(x-1))=0

We add all the numbers together, and all the variables

-3x-(-2x+3)-(2(x-1))=0

We get rid of parentheses

-3x+2x-(2(x-1))-3=0



We calculate terms in parentheses: -(2(x-1)), so:

2(x-1)

We multiply parentheses

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

-1x-(2x-2)-3=0

We get rid of parentheses

-1x-2x+2-3=0

We add all the numbers together, and all the variables

-3x-1=0

We move all terms containing x to the left, all other terms to the right

-3x=1

x=1/-3

x=-1/3

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