-x-3(1+8x)=8x-(x+3)

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Solution for -x-3(1+8x)=8x-(x+3) equation: 



-x-3(1+8x)=8x-(x+3)

We move all terms to the left:

-x-3(1+8x)-(8x-(x+3))=0

We add all the numbers together, and all the variables

-x-3(8x+1)-(8x-(x+3))=0

We add all the numbers together, and all the variables

-1x-3(8x+1)-(8x-(x+3))=0

We multiply parentheses

-1x-24x-(8x-(x+3))-3=0



We calculate terms in parentheses: -(8x-(x+3)), so:

8x-(x+3)

We get rid of parentheses

8x-x-3

We add all the numbers together, and all the variables

7x-3

Back to the equation:

-(7x-3)



We add all the numbers together, and all the variables

-25x-(7x-3)-3=0

We get rid of parentheses

-25x-7x+3-3=0

We add all the numbers together, and all the variables

-32x=0

x=0/-32

x=0

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