-x-3(x+2)=4(x-3)-2

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Solution for -x-3(x+2)=4(x-3)-2 equation: 



-x-3(x+2)=4(x-3)-2

We move all terms to the left:

-x-3(x+2)-(4(x-3)-2)=0

We add all the numbers together, and all the variables

-1x-3(x+2)-(4(x-3)-2)=0

We multiply parentheses

-1x-3x-(4(x-3)-2)-6=0



We calculate terms in parentheses: -(4(x-3)-2), so:

4(x-3)-2

We multiply parentheses

4x-12-2

We add all the numbers together, and all the variables

4x-14

Back to the equation:

-(4x-14)



We add all the numbers together, and all the variables

-4x-(4x-14)-6=0

We get rid of parentheses

-4x-4x+14-6=0

We add all the numbers together, and all the variables

-8x+8=0

We move all terms containing x to the left, all other terms to the right

-8x=-8

x=-8/-8

x=1

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