-x-38=2(2x-6)+8x

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Solution for -x-38=2(2x-6)+8x equation:



-x-38=2(2x-6)+8x
We move all terms to the left:
-x-38-(2(2x-6)+8x)=0
We add all the numbers together, and all the variables
-1x-(2(2x-6)+8x)-38=0
We calculate terms in parentheses: -(2(2x-6)+8x), so:
2(2x-6)+8x
We add all the numbers together, and all the variables
8x+2(2x-6)
We multiply parentheses
8x+4x-12
We add all the numbers together, and all the variables
12x-12
Back to the equation:
-(12x-12)
We get rid of parentheses
-1x-12x+12-38=0
We add all the numbers together, and all the variables
-13x-26=0
We move all terms containing x to the left, all other terms to the right
-13x=26
x=26/-13
x=-2

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