-x-4=3(2-3x)+6

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Solution for -x-4=3(2-3x)+6 equation: 



-x-4=3(2-3x)+6

We move all terms to the left:

-x-4-(3(2-3x)+6)=0

We add all the numbers together, and all the variables

-x-(3(-3x+2)+6)-4=0

We add all the numbers together, and all the variables

-1x-(3(-3x+2)+6)-4=0



We calculate terms in parentheses: -(3(-3x+2)+6), so:

3(-3x+2)+6

We multiply parentheses

-9x+6+6

We add all the numbers together, and all the variables

-9x+12

Back to the equation:

-(-9x+12)



We get rid of parentheses

-1x+9x-12-4=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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