-x-8+3x+6=-6(8x-7)+4(8x-2)

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Solution for -x-8+3x+6=-6(8x-7)+4(8x-2) equation: 



-x-8+3x+6=-6(8x-7)+4(8x-2)

We move all terms to the left:

-x-8+3x+6-(-6(8x-7)+4(8x-2))=0

We add all the numbers together, and all the variables

2x-(-6(8x-7)+4(8x-2))-2=0



We calculate terms in parentheses: -(-6(8x-7)+4(8x-2)), so:

-6(8x-7)+4(8x-2)

We multiply parentheses

-48x+32x+42-8

We add all the numbers together, and all the variables

-16x+34

Back to the equation:

-(-16x+34)



We get rid of parentheses

2x+16x-34-2=0

We add all the numbers together, and all the variables

18x-36=0

We move all terms containing x to the left, all other terms to the right

18x=36

x=36/18

x=2

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