-x/5-(2/5x=2

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Solution for -x/5-(2/5x=2 equation: 



-x/5-(2/5x=2

We move all terms to the left:

-x/5-(2/5x-(2)=0



Domain of the equation: 5x-2!=0

We move all terms containing x to the left, all other terms to the right

5x!=2

x!=2/5

x!=2/5

x∈R



We calculate fractions


=0

x=0/1

x=0

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