-x2+17x-60=0

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Solution for -x2+17x-60=0 equation:



-x2+17x-60=0
We add all the numbers together, and all the variables
-1x^2+17x-60=0
a = -1; b = 17; c = -60;
Δ = b2-4ac
Δ = 172-4·(-1)·(-60)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-7}{2*-1}=\frac{-24}{-2} =+12 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+7}{2*-1}=\frac{-10}{-2} =+5 $

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