-x2+34x-273=0

Solution for -x2+34x-273=0 equation:

-x2+34x-273=0

We add all the numbers together, and all the variables

-1x^2+34x-273=0

a = -1; b = 34; c = -273;
Δ = b2-4ac
Δ = 342-4·(-1)·(-273)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-8}{2*-1}=\frac{-42}{-2}
=+21
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+8}{2*-1}=\frac{-26}{-2}
=+13
$