-x2+60x-500=0

Solution for -x2+60x-500=0 equation:

-x2+60x-500=0

We add all the numbers together, and all the variables

-1x^2+60x-500=0

a = -1; b = 60; c = -500;
Δ = b2-4ac
Δ = 602-4·(-1)·(-500)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-40}{2*-1}=\frac{-100}{-2}
=+50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+40}{2*-1}=\frac{-20}{-2}
=+10
$