-x2+6=10

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Solution for -x2+6=10 equation: 



-x2+6=10

We move all terms to the left:

-x2+6-(10)=0

We add all the numbers together, and all the variables

-1x^2-4=0

a = -1; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·(-1)·(-4)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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