-x2+7x-5=0

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Solution for -x2+7x-5=0 equation:



-x2+7x-5=0
We add all the numbers together, and all the variables
-1x^2+7x-5=0
a = -1; b = 7; c = -5;
Δ = b2-4ac
Δ = 72-4·(-1)·(-5)
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{29}}{2*-1}=\frac{-7-\sqrt{29}}{-2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{29}}{2*-1}=\frac{-7+\sqrt{29}}{-2} $

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