-x2-5x+60=0

Solution for -x2-5x+60=0 equation:

-x2-5x+60=0

We add all the numbers together, and all the variables

-1x^2-5x+60=0

a = -1; b = -5; c = +60;
Δ = b2-4ac
Δ = -52-4·(-1)·60
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{265}}{2*-1}=\frac{5-\sqrt{265}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{265}}{2*-1}=\frac{5+\sqrt{265}}{-2}
$