-y+(4y-3)=12

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Solution for -y+(4y-3)=12 equation: 



-y+(4y-3)=12

We move all terms to the left:

-y+(4y-3)-(12)=0

We add all the numbers together, and all the variables

-1y+(4y-3)-12=0

We get rid of parentheses

-1y+4y-3-12=0

We add all the numbers together, and all the variables

3y-15=0

We move all terms containing y to the left, all other terms to the right

3y=15

y=15/3

y=5

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