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-y+2/3y=9
We move all terms to the left:
-y+2/3y-(9)=0
Domain of the equation: 3y!=0We add all the numbers together, and all the variables
y!=0/3
y!=0
y∈R
-1y+2/3y-9=0
We multiply all the terms by the denominator
-1y*3y-9*3y+2=0
Wy multiply elements
-3y^2-27y+2=0
a = -3; b = -27; c = +2;
Δ = b2-4ac
Δ = -272-4·(-3)·2
Δ = 753
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{753}}{2*-3}=\frac{27-\sqrt{753}}{-6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{753}}{2*-3}=\frac{27+\sqrt{753}}{-6} $
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