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-y+2=-2/5(y-5)
We move all terms to the left:
-y+2-(-2/5(y-5))=0
Domain of the equation: 5(y-5))!=0We add all the numbers together, and all the variables
y∈R
-1y-(-2/5(y-5))+2=0
We multiply all the terms by the denominator
-1y*5(y-5))-(+2*5(y-5))-2=0
Wy multiply elements
-5y^2(y+10y(y=0
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