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-y+3/2+(6/2)y=2y
We move all terms to the left:
-y+3/2+(6/2)y-(2y)=0
Domain of the equation: 2)y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
-y+3y-2y+3/2=0
We add all the numbers together, and all the variables
3/2=0
We multiply all the terms by the denominator
3!=0
There is no solution for this equation
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