-y+45+20y+58=2(3y+58)

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Solution for -y+45+20y+58=2(3y+58) equation: 



-y+45+20y+58=2(3y+58)

We move all terms to the left:

-y+45+20y+58-(2(3y+58))=0

We add all the numbers together, and all the variables

19y-(2(3y+58))+103=0



We calculate terms in parentheses: -(2(3y+58)), so:

2(3y+58)

We multiply parentheses

6y+116

Back to the equation:

-(6y+116)



We get rid of parentheses

19y-6y-116+103=0

We add all the numbers together, and all the variables

13y-13=0

We move all terms containing y to the left, all other terms to the right

13y=13

y=13/13

y=1

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