-y-4(2y+3)=15

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Solution for -y-4(2y+3)=15 equation: 



-y-4(2y+3)=15

We move all terms to the left:

-y-4(2y+3)-(15)=0

We add all the numbers together, and all the variables

-1y-4(2y+3)-15=0

We multiply parentheses

-1y-8y-12-15=0

We add all the numbers together, and all the variables

-9y-27=0

We move all terms containing y to the left, all other terms to the right

-9y=27

y=27/-9

y=-3

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