-y2+2=y-5

Solution for -y2+2=y-5 equation:

-y2+2=y-5

We move all terms to the left:

-y2+2-(y-5)=0

We add all the numbers together, and all the variables

-1y^2-(y-5)+2=0

We get rid of parentheses

-1y^2-y+5+2=0

We add all the numbers together, and all the variables

-1y^2-1y+7=0

a = -1; b = -1; c = +7;
Δ = b2-4ac
Δ = -12-4·(-1)·7
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{29}}{2*-1}=\frac{1-\sqrt{29}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{29}}{2*-1}=\frac{1+\sqrt{29}}{-2}
$