-z+3(2+4z)=6(z+1)+5z

Solution for -z+3(2+4z)=6(z+1)+5z equation:

Simplifying
-1z + 3(2 + 4z) = 6(z + 1) + 5z
-1z + (2 * 3 + 4z * 3) = 6(z + 1) + 5z
-1z + (6 + 12z) = 6(z + 1) + 5z

Reorder the terms:
6 + -1z + 12z = 6(z + 1) + 5z

Combine like terms: -1z + 12z = 11z
6 + 11z = 6(z + 1) + 5z

Reorder the terms:
6 + 11z = 6(1 + z) + 5z
6 + 11z = (1 * 6 + z * 6) + 5z
6 + 11z = (6 + 6z) + 5z

Combine like terms: 6z + 5z = 11z
6 + 11z = 6 + 11z

Add '-6' to each side of the equation.
6 + -6 + 11z = 6 + -6 + 11z

Combine like terms: 6 + -6 = 0
0 + 11z = 6 + -6 + 11z
11z = 6 + -6 + 11z

Combine like terms: 6 + -6 = 0
11z = 0 + 11z
11z = 11z

Add '-11z' to each side of the equation.
11z + -11z = 11z + -11z

Combine like terms: 11z + -11z = 0
0 = 11z + -11z

Combine like terms: 11z + -11z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.