-z+3(z-4)=4(z-1)

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Solution for -z+3(z-4)=4(z-1) equation:


Simplifying
-1z + 3(z + -4) = 4(z + -1)

Reorder the terms:
-1z + 3(-4 + z) = 4(z + -1)
-1z + (-4 * 3 + z * 3) = 4(z + -1)
-1z + (-12 + 3z) = 4(z + -1)

Reorder the terms:
-12 + -1z + 3z = 4(z + -1)

Combine like terms: -1z + 3z = 2z
-12 + 2z = 4(z + -1)

Reorder the terms:
-12 + 2z = 4(-1 + z)
-12 + 2z = (-1 * 4 + z * 4)
-12 + 2z = (-4 + 4z)

Solving
-12 + 2z = -4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-12 + 2z + -4z = -4 + 4z + -4z

Combine like terms: 2z + -4z = -2z
-12 + -2z = -4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-12 + -2z = -4 + 0
-12 + -2z = -4

Add '12' to each side of the equation.
-12 + 12 + -2z = -4 + 12

Combine like terms: -12 + 12 = 0
0 + -2z = -4 + 12
-2z = -4 + 12

Combine like terms: -4 + 12 = 8
-2z = 8

Divide each side by '-2'.
z = -4

Simplifying
z = -4

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