-z-3=4z+27

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Solution for -z-3=4z+27 equation: 



-z-3=4z+27

We move all terms to the left:

-z-3-(4z+27)=0

We add all the numbers together, and all the variables

-1z-(4z+27)-3=0

We get rid of parentheses

-1z-4z-27-3=0

We add all the numbers together, and all the variables

-5z-30=0

We move all terms containing z to the left, all other terms to the right

-5z=30

z=30/-5

z=-6

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