-z/12=3

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Solution for -z/12=3 equation: 



-z/12=3

We move all terms to the left:

-z/12-(3)=0

We multiply all the terms by the denominator


-z-3*12=0

We add all the numbers together, and all the variables

-1z-36=0

We move all terms containing z to the left, all other terms to the right

-z=36

z=36/-1

z=-36

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